bd007h

10-23-2005, 10:04 PM

here's a cake:

http://www.stillwaterpower.com/happy_birthday_cake_2.jpg

Hope you have a great day

http://www.stillwaterpower.com/happy_birthday_cake_2.jpg

Hope you have a great day

View Full Version : Happy Birthday to Skratch, Little_Miss_1565, and Willferno

bd007h

10-23-2005, 10:04 PM

here's a cake:

http://www.stillwaterpower.com/happy_birthday_cake_2.jpg

Hope you have a great day

http://www.stillwaterpower.com/happy_birthday_cake_2.jpg

Hope you have a great day

sKratch

10-23-2005, 10:06 PM

I'm just 20 :[

Thanks. Obviously, I'm the best because my name is first.

Thanks. Obviously, I'm the best because my name is first.

TheHulaChick

10-23-2005, 10:10 PM

Happy Birthday guys! have much birthday fun.

Rag Doll

10-23-2005, 10:14 PM

Happy birthday all of you =)

and hope you don't have a hangover as a birthday present, 1565 ;p

and hope you don't have a hangover as a birthday present, 1565 ;p

Betty

10-23-2005, 10:23 PM

Happy birthday to two very fantastic people!

If I were there, I would buy you a drink.

If I were there, I would buy you a drink.

GreenTerror

10-23-2005, 10:45 PM

Happy birthday. There's a fun birthday game you should all play. It's called "Kill someone for every year old you are" Yeah, so if you're 21, you kill 21 people. It's fun...

T-6005

10-23-2005, 11:20 PM

Here's to you being 21! Or 20! Or whatever, here's to it!

Mota Boy

10-24-2005, 12:35 AM

Thank You

I Am Very Drunk

And Very 21

Jesus, were those caps?

Happy Birthday and good luck with your head in the morn.

And Happy Birthday to sKratch too... even though twenty is just basically a countdown year.

I Am Very Drunk

And Very 21

Jesus, were those caps?

Happy Birthday and good luck with your head in the morn.

And Happy Birthday to sKratch too... even though twenty is just basically a countdown year.

Endymion

10-24-2005, 12:42 AM

you're both getting birthday calls. that is, IF sarah sends me her number (HINT HINT).

SkunkIt

10-24-2005, 12:44 AM

Happy Birthday, to all three of you!

http://www.comfortzonebaskets.com/gt_happybirthday.jpg

And cheers, Little_Miss_1565!

http://www.spaceshuttleinn.com/Durango/images/Margarita.jpg

http://www.comfortzonebaskets.com/gt_happybirthday.jpg

And cheers, Little_Miss_1565!

http://www.spaceshuttleinn.com/Durango/images/Margarita.jpg

Izie

10-24-2005, 12:46 AM

Yups, happy birthday all :):)

memento

10-24-2005, 01:22 AM

I wanna go to 1565's 21st it'd be bare mad.

nieh

10-24-2005, 03:50 AM

Happy Birthday!

TheUnholyNightbringer

10-24-2005, 05:39 AM

Haha, it's wonderful that people always check the BBS on their birthday. =D

Happy birthday all.

Happy birthday all.

sKratch

10-24-2005, 06:27 AM

Wooo, got to wake up early today to do Fourier transformations or something... Better be a good day after that.

Amanda

10-24-2005, 07:59 AM

Happy birthdays to all you 3!

Tizzalicious

10-24-2005, 08:32 AM

Happy Birthday you all!

Endymion

10-24-2005, 08:38 AM

Wooo, got to wake up early today to do Fourier transformations or something... Better be a good day after that.

lucky!

(HINT HINT)

for emphasis.

lucky!

(HINT HINT)

for emphasis.

memento

10-24-2005, 09:17 AM

I knew you were gonna say that Endy.

sKratch

10-24-2005, 09:24 AM

pssst... question.

How do I calculate <x> if <x>=int(Ψ^*Ψdx) if Ψ = A*exp(-(x-x0)^2/(2*a^2))exp(i*p0*x)/h-bar) and Ψ^* is the complex conjugate of Ψ?

How do I calculate <x> if <x>=int(Ψ^*Ψdx) if Ψ = A*exp(-(x-x0)^2/(2*a^2))exp(i*p0*x)/h-bar) and Ψ^* is the complex conjugate of Ψ?

memento

10-24-2005, 09:25 AM

omg you do that sKratch? That's some heavy shit.

sKratch

10-24-2005, 09:34 AM

Mmmm... well Ψ^*Ψ = w(x) = A^*A(exp(-(x-x0)^2/a^2), which through unit normalization is 1/(a(sqrt(pi))*exp(-(x-x0)^2/a^2)

so the integral becomes int(1/(a(sqrt(pi))*exp(-(x-x0)^2/a^2)dx)

We then let x-x0 = y, dy=dx, r=1/a so we have:

r/sqrt(pi)*exp(-y^2*r^2)dy, which is a gaussian integral. We must change the bounds from -inf..inf to 0..inf and multiply by 2 to use the integration table, and we get r/sqrt(pi)*(sqrt(pi)/2r)*2 = 1. I should get <x> = x though =/**

** I was missing an "x" multiplication term; <x>=int(Ψ^*Ψ*xdx)

So:

By letting x-x0 = y, x=y+x0

So we have the integral:

r/sqrt(pi)*(y+x0)exp(-y^2r^2)dy which can be rewritten as a sum of two integrals by distributing y+x0:

r/sqrt(pi)*x0*exp(-y^2r^2)dy + r/sqrt(pi)*y*exp(-y^2r^2)dy which gives:

x0 + r/sqrt(pi)*1/(2r^2) = x0 + 1/2r. However, I need the answer "x0". Where did I go wrong?

so the integral becomes int(1/(a(sqrt(pi))*exp(-(x-x0)^2/a^2)dx)

We then let x-x0 = y, dy=dx, r=1/a so we have:

r/sqrt(pi)*exp(-y^2*r^2)dy, which is a gaussian integral. We must change the bounds from -inf..inf to 0..inf and multiply by 2 to use the integration table, and we get r/sqrt(pi)*(sqrt(pi)/2r)*2 = 1. I should get <x> = x though =/**

** I was missing an "x" multiplication term; <x>=int(Ψ^*Ψ*xdx)

So:

By letting x-x0 = y, x=y+x0

So we have the integral:

r/sqrt(pi)*(y+x0)exp(-y^2r^2)dy which can be rewritten as a sum of two integrals by distributing y+x0:

r/sqrt(pi)*x0*exp(-y^2r^2)dy + r/sqrt(pi)*y*exp(-y^2r^2)dy which gives:

x0 + r/sqrt(pi)*1/(2r^2) = x0 + 1/2r. However, I need the answer "x0". Where did I go wrong?

memento

10-24-2005, 09:35 AM

speed = distance/time.

Endymion

10-24-2005, 10:45 AM

i have to run off for an "informal talk on anyions", but i've got the answer and i'll clean it up and scan it when i get back (around noon my time).

defy me

10-24-2005, 10:51 AM

Happy birthday have a great day

Kerr

10-24-2005, 12:18 PM

Happy birthday to y'all.

sKratch

10-24-2005, 12:18 PM

i have to run off for an "informal talk on anyions", but i've got the answer and i'll clean it up and scan it when i get back (around noon my time).

And that's why I love you. Feel free to make it a new thread, so as to avoid further physicization (wtf) of this one.

Thanks defy.

Edit: And kerr.

And that's why I love you. Feel free to make it a new thread, so as to avoid further physicization (wtf) of this one.

Thanks defy.

Edit: And kerr.

ninthlayer

10-24-2005, 01:22 PM

sKratch is so young, har har har.

sects?

sects?

sKratch

10-24-2005, 03:02 PM

wtf yes 1 2 3 4 5

do it on the butt

do it on the butt

Tizzalicious

10-24-2005, 03:04 PM

Oh yeah, I was gonna ask for sex too, but I couldn't because Per was still logged in with my account and he would probably edit it. But he is logged out now. So...sex?

the_offsprings_monkey

10-24-2005, 03:04 PM

are you and him going out or somethink?

Tizzalicious

10-24-2005, 03:06 PM

If you would use the photoalbum for what it's supposed to be for, instead of as a chatbox, you wouldn't as stupid questions like that. So I won't answer that.

the_offsprings_monkey

10-24-2005, 03:07 PM

I take that as a yes?

sKratch

10-24-2005, 03:15 PM

Oh yeah, I was gonna ask for sex too, but I couldn't because Per was still logged in with my account and he would probably edit it. But he is logged out now. So...sex?

Yes yes yes.

Yes yes yes.

Endymion

10-24-2005, 03:54 PM

you still owe me three thousand something blowjobs.

<3

<3

0r4ng3

10-24-2005, 03:55 PM

Wow, 3 people who matter have birthdays today? Awesome.

HB to all and such.

HB to all and such.

[Warning] Nimrod In Town

10-24-2005, 03:55 PM

you still owe me three thousand something blowjobs.

<3

What the fuck?! DELETE ALL THE GOD-DAMN SPAM!

<3

What the fuck?! DELETE ALL THE GOD-DAMN SPAM!

0r4ng3

10-24-2005, 03:56 PM

Damn nimrod, you could've just pm'd him.

Endymion

10-24-2005, 04:00 PM

Nimrod In Town']What the fuck?! DELETE ALL THE GOD-DAMN SPAM!

i had this thread open from when i was doing the quantum mechanics before. i just saw the five threads after posting and have deleted them.

i had this thread open from when i was doing the quantum mechanics before. i just saw the five threads after posting and have deleted them.

[Warning] Nimrod In Town

10-24-2005, 04:02 PM

Damn nimrod, you could've just pm'd him.

What would the point of that be?

What would the point of that be?

sKratch

10-24-2005, 04:13 PM

I unfortunately had to do a hard-reboot when quake 4 crashed my pc, so I lost exactly how many blowjobs I owe you. But let it be known that said quantity is large.

Human

10-24-2005, 04:15 PM

I command you to make a happy birthday thread for me on wednesday. I got my hair yukoed for it and my hair is dead straight now. My mom says that I'll get a surprise gift even though my parents already spent $500 on getting my hair yukoed. Yayayayayayayayayayayayayayayayay!!!!!

bd007h

10-24-2005, 04:16 PM

Yukoed? what the fuck does that mean?

Human

10-24-2005, 04:18 PM

Yukoed? what the fuck does that mean?

It is a fancy way of getting your hair permed but it is healthier and better for your hair and alot more expensive. It also sometimes lasts longer. It is called a yuko if you want the non plural noun of it.

It is a fancy way of getting your hair permed but it is healthier and better for your hair and alot more expensive. It also sometimes lasts longer. It is called a yuko if you want the non plural noun of it.

Endymion

10-24-2005, 05:28 PM

I unfortunately had to do a hard-reboot when quake 4 crashed my pc, so I lost exactly how many blowjobs I owe you. But let it be known that said quantity is large.

(13:28:11) sKratch zEro: alright, thanks a lot. i owe you like 3853 blowjobs.

(13:28:11) sKratch zEro: alright, thanks a lot. i owe you like 3853 blowjobs.

sKratch

10-24-2005, 08:50 PM

You owe me a dollar if that's a prime number.

Edit:

http://www.onlineconversion.com/prime.htm Yes.

Edit:

http://www.onlineconversion.com/prime.htm Yes.

HornyPope

10-24-2005, 11:25 PM

Happy bday y'all.

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