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Jojan
03-15-2007, 12:35 PM
Can somebody please get the U out from this formula? I want it so that it says U =
http://web.telia.com/~u87430085/problem.png (PNG, 1100x439 pix, 20 kB)

Here is the code for OpenOffice.org Math:

"I" = {5 cdot 2260 cdot e^{3200 over {273.15+"U"} - 3200 over 296.5}} over {2260 cdot e^{3200 over {273.15 + "U"} - 3200 over 296.5} - 5600}
Here is the code for Wikipedia:

<math>I = \frac{5 \cdot 2260 \cdot e^{\frac{3200}{273.15+U} - \frac{3200}{296.5}}}{2260 \cdot e^{\frac{3200}{273.15+U} - \frac{3200}{296.5}} -5600}</math>

If not the solution, do you have a suggestion on how to do it?

sKratch
03-15-2007, 12:45 PM
Multiply both sides by the denominator and take the natural log of each side. That's a start. Now time to eat a sandwich...

Jojan
03-15-2007, 02:50 PM
I made 2260 e^ -part to x and solved x out of I and U of x.

http://web.telia.com/~u87430085/solution.png Solution

Endymion
03-15-2007, 04:47 PM
so why did you ask us to do some basic algebra for you?

Jojan
03-16-2007, 12:58 AM
It wasn't really basic for me when I was tired and posted it.